Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule. a(n) = –6 + (n–1)(6) 6, 18, 54 –6, 12, 48 0, 18, 54 –6, 18, 54

Simplify:

A(n) = -6 + (n - 1)(6) = -6 + (n)(6) + (-1)(6) = -6 + 6n - 6 = 6n - 12

Put n = 1, n = 4 and n = 10 to the expression:

A(1) = 6(1) - 12 = 6 - 12 = -6

A(4) = 6(4) - 12 = 24 - 12 = 12

A(10) = 6(10) - 12 = 60 - 12 = 48