The figure below shows a rectangle abcd having diagonals ac and db: a rectangle abcd is shown with diagonals ac and bd. jimmy wrote the following proof to show that the diagonals of rectangle abcd are congruent: jimmy's proof: statement 1: in triangle adc and bcd, ad = bc (opposite sides of a rectangle are congruent) statement 2: angle adc = angle bcd (angles of a rectangle are 90°) statement 3: statement 4: triangle adc and bcd are congruent (by sas postulate) statement 5: ac = bd (by cpctc) which statement below completes jimmy's proof? ab=ab (reflexive property of equality) ab=ab (transitive property of equality) dc=dc (reflexive property of equality) dc=dc (transitive property of equality)

DC=DC (reflexive property of equality)

Step-by-step explanation:

The reflexive property of equality states that a value is equal to itself.

Given: ABCD is a rectangle,

Where AB, BC, CD, and DA are the sides of the rectangle while AC and BD are the diagonals of the rectangle. ( Shown in below diagram)

To prove: The diagonals of ABCD are congruent.

That is,

Proof:  In triangles ADC and BCD,

  ( Opposite sides of a rectangle are congruent )

 ( Angles of a rectangle are of 90° )

                ( Reflexive property of equality )  

Thus, By SAS postulate of congruence,

By CPCTC,

⇒ The diagonals of rectangle are congruent.                    

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step-by-step explanation:

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