The figure below shows a rectangle abcd having diagonals ac and db: a rectangle abcd is shown with diagonals ac and bd. jimmy wrote the following proof to show that the diagonals of rectangle abcd are congruent: jimmy's proof: statement 1: in triangle adc and bcd, ad = bc (opposite sides of a rectangle are congruent) statement 2: angle adc = angle bcd (angles of a rectangle are 90°) statement 3: statement 4: triangle adc and bcd are congruent (by sas postulate) statement 5: ac = bd (by cpctc) which statement below completes jimmy's proof? ab=ab (reflexive property of equality) ab=ab (transitive property of equality) dc=dc (reflexive property of equality) dc=dc (transitive property of equality)