Find all real numbers z for which the equation (z-5)x^2-zx+5=0 only has one real solution. i am giving

z = 5

x = 0

x = 1

Step-by-step explanation:

(z - 5)x^2 - (z - 5)x = 0          Take out z - 5 as a common factor

(z - 5)(x^2 - x)                        Take out x as a common factor

(z - 5)(x)(x - 1)                          Any one of these could equal 0. There are 3 solutons.

z - 5 = 0                                  Add 5 to both sides

z - 5 + 5 = 0 + 5

z = 5

x = 0

x - 1 = 0

x - 1 + 1 = 0 + 1    

x = 1

3.76%

step-by-step explanation: