The following data represent the amount of time (in minutes) a random sample of eight students took to complete the online portion of an exam in a particular statistics course. compute the mean, median, and mode time. 65.4, 79.5, 83.2, 113.5, 128.4, 99.3, 94.7, 115.2

Mean =   97.4

Median = 97

Mode = 0

Step-by-step explanation:

Here, the given data,

65.4, 79.5, 83.2, 113.5, 128.4, 99.3, 94.7, 115.2

Thus, total observation = 8

Since,

The arrangement of data in increasing order,

65.4, 79.5, 83.2, 94.7, 99.3, 113.5, 115.2, 128.4

Therefore,

⇒

⇒

Since, there is no repeated observation in the given data,

⇒ Given data has no mode.

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!