Problems 6, 7, 8show work if any you

6.  BM = 33

7.  M is the bisector; BM = 54 1/3

8. 1.8 cm

Step-by-step explanation:

6. The segments left and right of point M have a vertical hash mark indicating they are the same length. Then ...

  4x +13 = 3x +18

  x = 5 . . . . . . . . . . . subtract 3x+13 from both sides of the equation

  BM = 3x+18 = 3·5 +18 = 33

7. As in problem 6, the hash marks indicate that M is the midpoint between A and B, so M bisects AB.

  4x +1 = 7x - 39  . . . . . . . segments either side of M have the same length

  40 = 3x . . . . . . . . . subtract 4x-39 from both sides of the equation

  40/3 = x . . . . . . . . . divide by 3

  BM = 7x -39 = 7(40/3) -39 = (280 -117)/3 = 163/3

  BM = 54 1/3

8. Read the scale. The segment extends from 5 to 6.8, so has a length of ...

  6.8 -5 = 1.8 . . . cm

chad should not have included the values (1, 2) and (3, 6) because that would mean he only had half a healing card.

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.