(75 points) asap use a system of equations to solve this problem. bronze is a mix, or alloy, of tin and copper. a metal worker needs 100 g of bronze that is 25% tin. he has one tin/copper alloy that is 5% tin and another tin/copper alloy that is 45% tin. let x = the number of grams of the 5% tin alloy. let y = the number of grams of the 45% tin alloy. how many grams of each alloy should the metal worker combine? enter your answers in the boxes.

50 grams of 45% alloy and 50 grams of tin alloy

Step-by-step explanation:

Those are the two equations:

x+y=100

the sum of the weight of both alloys is 100 g

0.5x+0.45y=0.25*100

the sum of the weights of tin has to be 25% of 100g, which is actually 25 g

0.5x+0.45y=25

So we have:

x+y=100

0.5x+0.45y=25

x=10-y

0.5x+0.45y=25

We substitute:

0.5(10-y)+0.45y=25

We calculate:

5-0.5y+0.45y=25

-0.5y+0.45y=20

0.4y=20

4y=200

y=50

So he needs 50 grams of 45% alloy and 100-50=50 grams of tin alloy as well

cut 138 centimeters off

step-by-step explanation:

250-112 = 138

well if he bought them at 5 cedis each sold them at 7 cedis each then he would make a profit of 2 cedis of each book. if in total he made 150 cedis profit that means he sold 75 books. he lost 12 books at the start so that means he originally bought a total of 82 books.

step-by-step explanation: