Me. determine which consecutive integers have a real zero of the function f(x)=x^4-3x^3-2x^2+3x-5. between them. , -5), (3, 4) , -1), (3, 4) , -5), (-2, -1) d. (1, 2), (-4, -3)

b.(-2, -1), (3, 4)

Step-by-step explanation:

We are given function as

We can verify each intervals

At (-6,-5):

Firstly we will plug x=-6

now, we can plug x=-5

since, both are positive values

So, zeros can not lie between them

At (-4,-3):

Firstly we will plug x=-4

now, we can plug x=-3

since, both are positive values

So, zeros can not lie between them

At (-2,-1):

Firstly we will plug x=-2

now, we can plug x=-1

since, one is positive and another is negative

So, zeros will lie between them

At (3,4):

Firstly we will plug x=3

now, we can plug x=4

since, one is positive and another is negative

So, zeros will lie between them

zeros will be between

(-2, -1), (3, 4)

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions