The ratio of the numerator to the denominator of a fraction is 2 to 3. if both the numerator and the denominator are increased by 2, the fraction becomes 3/4 . what is the original fraction? which of the following systems of equations can be used to solve the problem?
a. n + 4 = 3 and d + 5 = 4
b. 3n - 2d = 0 and 4n + 2 = 3d + 2
c. 3n = 2d and 4n + 8 = 3d + 6

The fraction is

Option (B) is correct.

 and

Step-by-step explanation:

Let n denotes numerator and d denotes denominator of the fraction.

Given : The ratio of the numerator to the denominator of a fraction is 2 to 3.

That is

Cross multiply , we get,

Or,   ........(1)

Also, given : . If both the numerator and the denominator are increased by 2, the fraction becomes 3/4

That is

Cross multiply , We get,

 .........(2)

 .......(3)

Thus, from (1) and (2) , option (B) follows.

Solving equation (1) and (3) to get the original fraction using elimination method,

3n - 2d = 0    ............(1)

and 3d - 4n = 2       .........(3)

Multiply equation (1) by 3 , we get ,

9n - 6d = 0  ..........(4)

Multiply equation (3) by 2 , we get ,

-8n + 6d = 4 ..........(5)

Adding (4) and  (5) , we get,

9n - 6d -8n + 6d = 4 + 0

⇒ n = 4

Put n = 4 in (1), we get

3n - 2d = 0 ⇒ 3(4) - 2d = 0 ⇒ 12 -2d = 0  ⇒  12 = 2d ⇒ d = 6

so, the numerator is 4 and  the denominator is 6.

Thus, the fraction is

126.66 m²

step-by-step explanation:

the pertinent area formula is a = πr², where r is the radius.

here, a = π(6.35 m)² = 40.32π, or approximately 126.66 m²