Alocal community college determines the probability that a student will reenroll for a second year is 0.91. a representative surbeys 100 random first year students and asks them if they will be enrolling for the next year. what is the probability that exactly 91 of them wil enroll?

The probability is 0.1381, or about 13.8%

Step-by-step explanation:

The probability of a count k out of n with a known event probability p is described by the binomial distribution:

We are given n=100, p=0.91 and are asking for the probability of seeing exactly k=91 positive events (enrollment), so:

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.

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step-by-step explanation: