What is the probability of rolling a 6 and then a 1 on consecutive rolls of a standard, 6-sided number cube?

Hello from MrBillDoesMath!

1/36

Discussion:

The events of are unrelated ("mutually exclusive") so the probability of both happening is the product of the individual probabilities.  That is,

(1/6) * (1/6) = 1/36

Thank you,

MrB

1/36 chance

Step-by-step explanation:

You find the probability by finding the amount of the number you roll over the total choices that you can roll. In this example, there is one 6 on the dice and there are 6 different possibilities of numbers you can roll. That means the probability of rolling a 6 is 1/6. It would be the same if you were rolling a one because there is one 1 on the dice and there are 6 different possibilities of numbers you can roll. You would multiply each probability to find the probability of rolling both numbers. 1/6 * 1/6 is equal to 1/36, therefore, that is the probability of rolling a 6 and then a 1.

2? if not the correct answer you might need to provide more information

step-by-step explanation:

the opening of this porabola is facing up

step-by-step explanation: