What is the equation of the line perpendicular to 2x-3y=13 that passes through the point (-6,5)?

The slope-intercept form of a line:

m - slope

b - y-intercept

Convert 2x - 3y = 13 to the slope-intercept form:

       subtract 2x from both sides

       divide both sides by (-3)

Let and .

We have therefore

Equation of a line:

Put the coordinates of the point (-6, 5) to the equation of a line:

       subtract 9 from both sides

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.