Abag contains 3 red and 5 green sweets. tim takes a sweet at random and eats it. he then takes another sweet. what is the probability that tim takes 2 red sweets

The probability that Tim take 2 red Sweet without replacement is 0.0476

Given the Parameters :

Probability = Required outcome / Total possible outcomes

P(2 red sweets) = P(red) × P(red)

Since, selection is without replacement ;

P(2 red sweets) = 2/7 × 1/6 = 0.0476

Therefore, the probability of picking two red sweets is 0.0476

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Step-by-step explanation:

Given : A bag contains 3 red and 5 green sweets. Tim takes a sweet at random and eats it.

Total sweets were in bag = 5+3=8

Number of ways to select 2 red sweets =

Number of ways to select any two sweets =

Now, the probability that Tim takes 2 red sweets is given by :-

Hence, the probability that Tim takes 2 red sweets is .

inch

step-by-step explanation:

yard and mile are too big.

graph b

step-by-step explanation:

one solution- graph a (clear intercepting point.)

no solution- graph b (they're parallel, there will never be a point of interception.)

infinite solutions- graph c (all points intercept.)