Can you me solve systems of equations by elimination step by step 6x+y=15 -7x-2y=-10

  (4, -9)

Step-by-step explanation:

Use elimination method.  Manipulate one (or both) equations to eliminate one of the variables and solve for the remaining variable.  I will be eliminating y

6x +  y =  15    → 2(6x +  y =  15)   →   12x + 2y = 30

-7x - 2y = -10   → 1(-7x + 2y = -10)   →   -7x - 2y = -10

                                                             5x        = 20

                                                               x         =  4

Next, replace "x" with "4" into either equation and solve for y.

6(4) + y = 15

24  + y = 15

         y  = -9

Check:

Plug in x = 4 and y = -9 into the other equation to verify it makes a true statement.

-7x - 2y = -10

-7(4) - 2(-9) = -10

-28  -   -18  = -10

-28  +  18 = -10

       -10    =  -10  

i wish i could u

step-by-step explanation:

i wish i could u

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.