Q=12nv2 the dynamic pressure q generated by a fluid moving with velocity v can be found using the formula above, where n is the constant density of the fluid. an aeronautical engineer users the formula to find the dynamic pressure of a fluid moving with velocity v and the same fluid moving with velocity 1.5v. what is the ratio of the dynamic pressure of the faster fluid to the dynamic pressure of the slower fluid?

Because V is raised to the second power in the original equation the velocity of the slower fluid is V^2.

The faster fluid is 1.5V, which when replaced in the equation becomes 1.5v^2.

The ratio would then be 1.5^2 which equals 2.25

The ratio is 2.25/1

Step-by-step explanation:

Fluid 1

Q = 12 n v^2

Fluid 2

Q =12 n (1.5 v)^2

    =12 n (2.25) v^2

Ratio of the faster fluid to the slower fluid

Fluid 2/Fluid 1

12 n (2.25) v^2

12 n v^2

Canceling 12 and n

(2.25) v^2

v^2

Canceling v^2

2.25

1

The ratio is 2.25/1

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step-by-step explanation:

c.   x=2.4cm

step-by-step explanation:

similar triangles are triangles which have the same shape but not the same size. this means their angle measures are equal but their side lengths are not instead they are proportional. to solve, we will set up a proportion and solve.

a proportion is two equal ratios set equal to each other. we form the ratios by finding corresponding sides (sides which match to each other on both triangles by their position). out ratios will be one side of the small triangle over the corresponding side on the big triangle as shown below:

.

to solve the proportion, we'll cross multiply by multiplying numerator with denominator across the equal sign.