Find the area of a square with side, s = 2x + 3. hint: a = s2

A = 4x² + 12x + 9

Step-by-step explanation:

area of a square = s² ( s is the length of the side of the square )

here s = 2x + 3, hence

A = (2x + 3)² = (2x + 3)(2x + 3)

To expand multiply each term in the second factor by each term in the first factor

A = 2x(2x + 3) + 3(2x + 3) ← distributing

   = 4x² + 6x + 6x + 9 ← collect like terms

   = 4x² + 12x + 9

b.-4 units

all you   do is count how many times you move

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)