The rectangle shown has a perimeter of 40cm and the given area of 64 cm squared it's length is 8 more than twice its width write and solve a system of equations to find the dimension of the rectangle

16 = l

4 = w

Step-by-step explanation:

{64 = wl

{40 = 2w + 2l

{l = 8 + 2w

64 = w[8 + 2w] ↷

-64 + 8w + 2w² ↷

[2w² - 8w] + [16w - 64]

2w[w - 4] 16[w - 4]

[w - 4][2w + 16] = 0

↑

This is the expression we want because when we talk about dimensions, we want NON-NEGATIVE numbers. The other expression results in -8 = w, and we do not want that; this expression gives us a solution of 4 = w, and THIS is exactly what we want. Anyway, you plug "4" back into the system of equations and you will get a length of 16 centimetres.

I am joyous to assist you anytime.

it could be a ..idk tho

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations: