Its due what is the solution to the system of equations? 3x-6y=-12 x-2y=-8 (a)use the substation method to justify that the given system of equations had no solution. show all work! (b) what do you know about the two lines in this system of equations?

Step-by-step explanation:

3x- 6y= -12

and:

x-2y= -8 here, add 2y to both sides and you get:

x = 2y-8 Now, in the equation above, substitute for x:

3(2y-8)-6y = -12 distribute the 3 over the terms in parenthesis:

6y-24-6y = -12

Add 24 to both sides:

6y-6y = 12

0y = 12

Since y cannot be 0, this problem has no solution.

To plot lines you have to find the ordered pairs:

3x-6y = -12

6y = 3x+12

y = 3/6x+12/6

y = 1/3x+2

set x to 0:

y = 0x+2

y = 2

now we have an ordered pair, a dot on the graph: (x, y) = (0, 2)

Solve for y = 0:

3x-6y = -12

3x = 6y-12

x = 6y/3-12/3

x = 2y-4

set y to 0

x = 0y-4

x = -4

our second ordered pair is (-4, 0)

If you want, you can mark the two point on a graph and trace a line joining the two.

You do the other equation following my example and find out if they have any points in common.

a) one student is chosen from classroom a, then a student is chosen from classroom b.  

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b.   this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes.   this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes.   this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes.   this makes them dependent events.