Asap i will mark u brainliest a factory begins making tortillas in the morning, and it continues making tortillas throughout the day at a nearly constant rate. at noon, mr. nichols starts collecting data about the total number of tortillas made. he updates his data every half hour, and at the end of the day he creates the given graph to display the data. the linear equation shown below can be used to model the data, where x is the time, in hours, and y is the number of tortillas produced.

The blue line starts at Y=35, which means it started with 35,000 tortillas.

When x is at 2 hours the line crosses at Y = 60. so there were 60,000 tortillas produced at 2 hours.

When Y is at 85 ( 85,000, the X value is 4 hours.

1). 35000 tortillas

2). 60000 tortillas

3). 4 hours

Step-by-step explanation:

Mr Nichols updates his data every half hour about the total numbers of tortillas made.

The equation models the data in terms of x (time) and y (numbers of tortillas produced) is

y = 12000x + 35000

Now we will solve the question asked one by one.

1). When Mr Nicholas started recording the data number of tortillas produced.

At x = 0,  y = 12000×0 + 35000 = 0 + 35000

y = 35000 tortillas.

2). Total number of tortillas produced 2 hours after he began recording the data.

By analyzing the graph we find at x = 2 value of y was 60000 tortillas.

3). After how much time total numbers of tortillas produced were 85000.

As it is clear from the graph at y = 85000 value of x is 4 hours.

a

step-by-step explanation:

a

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.