What is the smallest possible area of an isosceles triangle with side lengths 5 inches and 6 inches? express your answer as a decimal to the nearest tenth.

A. p = 2(l + w)p/2 - l = ww = p/2 - l b. while isolating the variable w in the equation, i first divided both sides by 2 and then i subtracted l from both sides. i hope this .