6. regroup the numbers in the following problems, putting the numbers that add up to 10 or a multiple of 10 in parentheses. a. 2 + 9 + 8 b. 3 + 5 + 4 + 7 c. 4 + 2 + 16 d. 31 + 4 + 9

a) (2+8)+9

b) (3+7)+5+4

c) (4+16)+2

d) (31+9)+4

Step-by-step explanation:

a) 2+9+8

2 and 8 add up to 10, so we regroup them in parentheses

(2+8)+9

b) 3 + 5 + 4 + 7

3 and 7 add up to 10, so we regroup them in parentheses

(3+7)+5+4

c) 4 + 2 + 16

4 and 16 add up to 20 which is a multiple of 10, so we regroup them in parentheses

(4+16)+2

d) 31 + 4 + 9

31 and 9 add up to 40 which is a multiple of 10, so we regroup them in parentheses

(31+9)+4

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.

( - 4 , -7 )

all the lines must parallel  

step-by-step explanation:

coordinates of c = ( - 1 , 2 )

3 units left = ( -4 , 2 )

9 units down = ( - 4 , 11 )