The perimeter of a basketball court is 266 ft, and its length is 35 ft more than its width. find the dimensions of the court.

w = 49 ft and l = 84ft

Step-by-step explanation:

P = 266

The formula for perimeter = 2(l+w)

We know the length is 35 more than the width

l = w+35

Substituting in for Perimeter

266 =2(l+w)

Now replacing l with w+35

266 =2(w+35+w)

Combine like terms

266 = 2(2w+35)

Divide each side by 2

266/2 = 2/2 (2w+35)

133 = 2w+35

Subtract 35 from each side

133-35 = 2w+35-35

98 = 2w

Divide by 2

98/2 = 2w/2

49 =w

We still need to find l

l = w +35

l = 49+35

l = 84

it has the same slope and a different y-intercept

hope this : )

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.