The vertices of triangle r's't' are r'(1, 3), s'(6, 4), and t'(4, 2). if triangle rst was dilated about the origin with a scale factor of 3, what are the coordinates of its vertices?

R(1/3, 1), S(2, 4/3), T(4/3, 2/3)

Step-by-step explanation:

Dilation by a factor of 3 about the origin multiplies each coordinate by 3. To find what was multiplied by 3 to get the given coordinates, we divide the given coordinates by 3.

R  (1/3 ,1)

S = (2,4/3)

T= (4/3,2/3)

Step-by-step explanation:

RST  becomes R'S'T'  by multiplying by 3

To get back to RST we need to divide by 3

R =(1/3, 3/3) = (1/3 ,1)

S =(6/3,4/3) = (2,4/3)

T= (4/3,2/3)

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: