Lisa and shreya are selling pies for a school fundraiser. customers can buy apple pies and pumpkin pies. lisa sold 8 apple pies and 4 pumpkin pies for a total of $80. shreya sold 8 apple pies and 3 pumpkin pies for a total of $72. find the cost for one apple pie and pumpkin pie. apple: $4 , pumpkin: $10 apple: $2 , pumpkin: $13 apple: $6 , pumpkin: $8 apple: $5 , pumpkin: $4

The cost of one apple pie =  $6

And cost of one pumpkin pie = $8

Step-by-step explanation:

Let the cost of one apple pie be $x

And cost of one pumpkin pie be $ y.

According to given problem,

For Lisa :  sold 8 apple pies and 4 pumpkin pies for a total of $80

8x + 4y = 80   (1)

For Shreya :  sold 8 apple pies and 3 pumpkin pies for a total of $72

8x + 3y = 72    (2)

Solving equation (1) and (2), to get x and y.

Subtract equation (2) from equation (1)

i.e 8x + 4y - (8x +3y) = 80 - 72

or 8x - 8x + 4y - 3y = 8

or  y = 8

And x = 6   { 8x + 4×8 = 80   or x = (80 - 32)/8  = 48/8 = 6 }

Hence, the cost of one apple pie = x = $6

And cost of one pumpkin pie = y =$8

y=1/4x-4

step-by-step explanation: