Consider square abcd with vertices at a(−8,19), b(2,−5), c(−22,−15), and d(−32,9). what is the area, in square units, of square abcd?

Step-by-step explanation:

1. To solve this problem you must apply the formula for calculate the area of a square, which is:

Where s is the lenght of a side of the square.

2. By definition, the sides of the square have equal lenghts. You can calculate the lenght of a side by calculating the distance between two vertices of the aquare:

Where is the lenght of the side AB.

3. The area is:

answer: 1 + 1 = 11

step-by-step explanation:

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w