The hypotenuse of a right triangle is 15 cm and the shorter leg is 9cm find the length of the other leg

12 cm is your answer

Step-by-step explanation:

Use the equation: a² + b² = c² , in which c is the hypotenuse, and a & b are the other sides.

Note that the hypotenuse is 15, and the shorter leg is 9 cm. Plug in the corresponding numbers into the corresponding variables

a² + (9)² = (15)²

Simplify. First, solve for the solvable squares

a² + 81 = 225

Isolate the variable a. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS. First, subtract 81 from both sides:

a² + 81 (-81) = 225 (-81)

a² = 225 - 81

a² = 144

Isolate the variable a. Root both sides.

√(a²) = √(144)

a = √144 = √(12 * 12) = 12

a = 12

12 cm is your answer

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f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option