What number must you add to complete the square x^-8x=39

The number must be added to complete the square is  16

Step-by-step explanation:

It is given that,

x^2 - 8x = 39    (1)

The quadratic equation is of the form ax^2  + bx + c =0

To complete the square we have to add (b/2)^2 and subtract (b/2)^2

Therefore the eq (1) becomes

here b= -8, so we have to add (8/2)^2 = 4^2 = 16

Therefore the number is 16

To find x

x^2 - 8x  = 39

Add 16 to both sides

x^2 - 8x +16  = 39 + 16

(x - 4)^2 = 55

x - 4 = √55

x = √55 -4

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step-by-step explanation:

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