The base of an auditorium is in the form of an eclipse 200 feet long and 100 feet wide a pin drop near one focus can clearly be heard at the other focus determine the distance between the foci to the nearest 10th of a how would i work this out? ?

Let the coordinate of focus be

As per the statement: The base of an auditorium is in the form of an eclipse 200 feet long and 100 feet wide.

⇒Length of Major axis=base of an auditorium = 200 feet and Length of a minor axis=wide of a auditorium = 100 ft

Semi-major axis (a) = 100 ft and

semi-minor axis(b) = 50 ft

Then, by an equation:

Solve for c:

Substitute the given values we have;

Simplify:

or

ft

Distance between the foci is,  

Therefore, the distance between the foci to the nearest 10th of a foot is, 173.2 ft

the slope of the line is 60

one point on the line is (40,10)

step-by-step explanation:

in the equation outside the parenthesis the equation always tells you the slope. in this case it is 60.

in the parenthesis is also says 40 which is x because it is near the x and 10 is y because it is near y.

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!