The inequality x2 − 9 x2 + 6x + 8 > 0 can be factored as: (x + 3)(x - 3) (x + 4)(x + 2) > 0 use the critical points to determine the test regions. which are possible test points? –5 –4 –3.5 –3 –2.5 –2 0 5

The answers are:

-5

-3.5

-2.5

0

5

Step-by-step explanation:

The possible test points are -5,-3.5 , -2.5,0,5      

Step-by-step explanation:

Given : The inequality can be factored as

(x + 3)(x - 3) (x + 4)(x + 2) > 0

To find : Which are possible test points?

Solution : The inequality factored as

The critical points are defined as when we equation the factor to zero then the value of x is the critical point.

So, x+3=0 ⇒ x=-3

x-3=0 ⇒ x=3

x+4=0 ⇒ x=-4

x+2=0 ⇒ x=-2

The critical points of the given inequality are -4,-3,-2,3

The possible test points are the points except critical points.

Therefore, Out of the given options

The possible test points are -5,-3.5 , -2.5,0,5 as they are not critical points.

step-by-step explanation:

no of data

divide by no of mode

correct

step-by-step explanation: