If 4a - 13 = 6b + 35 = 8c -17 = d, find the smallest possible value of a + b + c + d.(they are integers)

The smallest possible value of a+b+c+d is: 4

Step-by-step explanation:

since we are given that:

4a - 13 = 6b + 35 = 8c -17 = d

on taking the first two equality i.e. 4a-13=6b+35

we get

on using the first and third equality we have:

4a-13=8c-17

also from the first and last equality we have:

d=4a-13

Hence,

the smallest possible value such that the expression a+b+c+d is positive will be claculated as:

a+b+c+d>0

that means

But as a is an integer, hence the smallest such value is 4.

answer: 0+0=0

step-by-step explanation:

that is the only answer that can make 0

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18