What polynomial has roots of −4, −1, and 6? x3 − 9x2 − 22x + 24 x3 − x2 − 26x − 24 x3 + x2 − 26x + 24 x3 + 9x2 + 14x − 24

 The answer is (b)

Step-by-step explanation:  We are given four polynomials and we are to check which one of them has roots -4, -1 and 6. Obviously, if putting these three values of 'x' in a polynomials yields 0, then that particular value will be a root of that polynomial.

Let us denote the polynomials as follows -

Let us check for x = -1 first. So, substituting x = -1 in all the four polynomils, we get

Therefore, only possibility is Q(x).

If we put x = -4 and x = 6 in Q(x), we find that

Thus, the correct option is (b)

y=−9/2x+10

step-by-step explanation:

let's solve for y.

0−9x−2y=−20

step 1: add 9x to both sides.

−9x−2y+9x=−20+9x

−2y=9x−20

step 2: divide both sides by -2.

−2y

−2

=

9x−20

−2

y=

−9

2

x+10