Bao is mixing flour and water to make dough. the graph shows how much water he uses for different amounts of flour. how many liters of water does bao use per liter of flour? how many liters of flour does bao use per liter of water?

0.33 liters of water Bao use per liter of flour.

3  liters of flour Bao use per liter of water

Step-by-step explanation:

Given the graph which pass through the coordinates (0,0) and (3,1)

∴ Equation of line passing through these points can be written as

⇒  

⇒ ⇒

Now, we have to find liters of water Bao use per liter of flour i.e if x=1 then we find the value of y which is 3y=x=1 ⇒

Now, we have to find  liters of flour Bao use per liter of water i.e if y=1 the we have to find the value of x which is x=3 litre

i think it's eleven too, don't woosh me here, but according to the "experts" it's 2.

the proof starts from the peano postulates, which define the natural

numbers n. n is the smallest set satisfying these postulates:

  p1.   1 is in n.

  p2.   if x is in n, then its "successor" x' is in n.

  p3.   there is no x such that x' = 1.

  p4.   if x isn't 1, then there is a y in n such that y' = x.

  p5.   if s is a subset of n, 1 is in s, and the implication

      (x in s => x' in s) holds, then s = n.

then you have to define addition recursively:

  def: let a and b be in n. if b = 1, then define a + b = a'

      (using p1 and p2). if b isn't 1, then let c' = b, with c in n

      (using p4), and define a + b = (a + c)'.

then you have to define 2:

  def:   2 = 1'

2 is in n by p1, p2, and the definition of 2.

theorem:   1 + 1 = 2

proof: use the first part of the definition of + with a = b = 1.

      then 1 + 1 = 1' = 2   q.e.d.

note: there is an alternate formulation of the peano postulates which

replaces 1 with 0 in p1, p3, p4, and p5. then you have to change the

definition of addition to this:

  def: let a and b be in n. if b = 0, then define a + b = a.

      if b isn't 0, then let c' = b, with c in n, and define

      a + b = (a + c)'.

you also have to define 1 = 0', and 2 = 1'. then the proof of the

theorem above is a little different:

proof: use the second part of the definition of + first:

      1 + 1 = (1 + 0)'

      now use the first part of the definition of + on the sum in

      parentheses:   1 + 1 = (1)' = 1' = 2   q.e.d.

cluster sampling.

step-by-step explanation: