Given h(t)=-2(t+5)^2 find h(-8) 334 –14 45 445

h(-8) = -18

Step-by-step explanation:

It is given that,

h(t)=-2(t+5)^2    (1)

To find h(-8)

Substitute t = -8  in equation (1)

h(-8) = -2(-8 + 5)^2

h(-8) = -2(-3)^2

h(-8) = -2 x 9 = -18

therefore the value of h(-8) = -18

But there is no option with value h(-8) = -18

215.92 dollars is the answer

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.