Correct answers only !

graph.

Vertex = (3, -1), 2nd point = (4, 0)

Step-by-step explanation:

f(x) = (x - 2)(x - 4)

The x-intercepts (when y = 0) are: x - 2 = 0 and x - 4 = 0  → x = 2 & x = 4

The x-value of the vertex is the midpoint of the zeros.  The midpoint between x = 2 and x = 4 is x = 3

The y-value of the vertex can be found by plugging the x-value (above( into the given equation: f(3) = (3 - 2)(3 - 4)  =  (1)(-1)  =  -1

So, the vertex is (3, -1)   ←    PLOT THIS COORDINATE

Additional points are: (2, 0) and (4, 0)  ←  PLOT ONE OF THESE

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3