The area of the indoor sports exhibition is shown below. use the following formulae: perimeter of a rectangle = 2l + 2w circumference of a circle = πd, π= 3.14 area of a rectangle = lw area of a circle = πr what is its perimeter? m what is its area? m2

Area: 3098 m^2

Perimeter: 356 m

Step-by-step explanation:

First find the area of the indoor sports park. Start by finding the area of the two rectangles using length times width (as shown in the first attachment).

Find the area of the half circle by finding the area of a circle () then dividing by 2.

Rect. 1 + Rect. 2 + Circle = Area

2244 + 400 + 908 (div'd by 2) = 3098 m^2

Don't know what happened to the image but you get the idea.

The perimeter of the rectangles were found by adding up all the side lengths, and the perimeter (circumference) of the circle was found by using .

Rect. 1 + Rect. 2 + Circle = Perimeter

202 + 100 + 107 (div'd by 2) = 355.5 (or 356) m

d

step-by-step explanation:

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