The vertex of the graph of y = -4(x + 3)2 + 2 is

The vertex is (-3, 2)

The equation y = -4(x + 3)^2 + 2 can be written as y = -4(x - (-3))^2 + 2

I rewrote x+3 as x - (-3)

Compare y = -4(x - (-3))^2 + 2 with the general template y = a(x-h)^2 + k

Note how

a = -4

h = -3

k = 2

So the vertex is (h,k) = (-3, 2)

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step-by-step explanation:

apex answer

the line of