June had $240 more than siti. junr gave 25% of her money to siti. siti then gave 20% of her money to june. how much more money did june have in the end?

$144

Step-by-step explanation:

Let the money which Siti has be x

Therefore, the money June has will be x+240

First condition is that June gave 25% of her money to Siti, So this amount will be deducted from June's money and will be added in Siti's money.

Siti's money = x+ [25%(x+240)]       June's money = x+240-[25%(x+240)]

                   = 1.25x + 60                                       = 0.75x + 180

Second condition is that Siti now gave 20% of her money to June.This amount will be deducted form Siti's money and added in June's money.

Siti's money = 1.25x+60-[20%(1.25x+60)]    

                    = x+48

June's money = 0.75x +180+[20%(1.25x+60)]

                        = x+192

Difference between Sitit and June's money = x+192-x-48

                                                                        = 144

Hence, June has $144 more money than Siti.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}