Ab passes through a(-3, 0) and b(-6, 5). what is the equation of the line that passes through the origin and is parallel to ab ? a. 5x − 3y = 0 b. -x + 3y = 0 c. -5x − 3y = 0 d. 3x + 5y = 0 e. -3x + 5y = 0

3y + 5x = 0

Step-by-step explanation:

The slope of the line = (y2-y1) / (x2-x1) = (5-0)/(-6-(-3))

= 5 / -3 = -5/3

Using the point-slope form , the line that passes through the origin and parallel to this line is

y - 0 = -5/3(x - 0)

y = -5/3 x

Multiply through by 3:-

3y = -5x

5x + 3y = 0

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step-by-step explanation: