Da shari wants to rearrange the four sweaters, two coats, and five jackets that are in her closet. if she puts a sweater first and a jacket last, how many different ways can she arrange them?

Solution:

Fabric possessed by Da. Shari = 4 Sweaters + 2 Coats + 5 Jackets= 11 in all

Arrangement that Da Shari wants to arrange 4 Sweaters + 2 Coats + 5 Jackets is to put  "a sweater first and a jacket last".

After putting a sweater first and jacket last , total fabric which needs to be arranged is (3 Sweaters + 2 Coats + 4 Jackets)=9 in all.

Total number of possible arrangement = (1 sweater) × [9 fabric=(3 Sweaters + 2 Coats + 4 Jackets) arrangement] × (1 Jackets)

     = 1! × 9 ! × 1!

    = 9 !

    = 9 × 8 × 7× 6× 5× 4× 3×2×1

    = 362,880 ways

1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

i hope this you, and have a wonderful day!