What are the vertices of the hyperbola with equation 4y^2 -25x^2=100

(0,-5) and (0,5).

Step-by-step explanation:

We have been given that an equation of hyperbola .

First of all we will convert our given equation into the standard form of hyperbola.

Let us divide both sides of our equation by 100.

Since we know that the positive term in the equation of a hyperbola determines whether the hyperbola opens in the x-direction or in the y-direction. Our hyperbola has a positive term, so it opens in the y-direction (up and down).  

The equation of a vertical hyperbola is :, where -a and a are vertices of our hyperbola.

Upon comparing our equation with vertical hyperbola equation we can see that vertices of our hyperbola will be (0.-5) and (0,5).

42

step-by-step explanation:

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.