What is the equation of the line that passes through the points (3,-2) and (-1,2) a) y=-x+1 b) y=-2x-2 c) y=-2x+4 d) y=-x+4 is it a, b,c, or d

A. y = -x + 1

Step-by-step explanation:

First find the slope of the two lines using the slope formula: .

Now use one of the two points; I am going to use (-1, 2).

Substitute the point and slope into the point-slope equation: y - y1 = m(x - x1).

y - (2) = -1(x - (-1))

Simplify.

y - 2 = -1x - 1

Add 2 to both sides and remove the 1 in front of the x. It is not needed.

y = -x + 1

if you was gonna solve for a, a is a   < -12

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92