Two students from a group of eight boys and 12 girls are sent to represent the school in a parade if the students are chosen at random what is the probability that the student is chosen or not both girls

62/95,

Step-by-step explanation:

62/95, or 0.6526

Step-by-step explanation:

To solve this, we fill find the probability that both students chosen are girls.  We will then find the complement of this, which will be that not both students are girls.

First we find the number of ways we can choose 0 boys from a group of 8.  This is the combination

Next we find the number of ways we can choose 2 girls from a group of 12.  This is the combination

This gives us 1*66 = 66 ways the event "both students are girls" can happen.

Next we find the total number of ways to choose 2 students out of this group.  There are a total of 8+12 = 20 students; this is the combination

This gives us the probability 66/190, which simplifies to 33/95.

We want the complement of this.  That means we subtract this probability from 1:

1-33/95 = 62/95 = 0.6526

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.