Suppose a triangle has three sides of length of 3 and 4 in that the angle between these two sides is 60°. what is the length of the third side of the triangle

3.61 in. to the nearest hundredth.

Step-by-step explanation:

You use the Cosine Rule to solve this.

a^2 = b^2 + c^2 - 2bc cos 60    where a is the third side.

Plugging in the given values:_

a^2  = 3^2 + 4^2 - 2*3*4* cos 60

=   9 + 16 - 24*0.5

=  13

a = √13

= 3.61

geometry: triangles

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answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584

it is x=-4

step-by-step explanation: