Prove that this is a right triangle, show work sides 2√5 2√5 2√10

The triangle has sides a,b,c such that

a = 2*sqrt(5), b = sqrt(5), and c = 2*sqrt(10)

Square each value

a = 2*sqrt(5)

a^2 = (2*sqrt(5))^2

a^2 = 2^2(sqrt(5))^2

a^2 = 4*5

a^2 = 20

b^2 = 20 for similar reasons as side 'a'

c = 2*sqrt(10)

c^2 = (2*sqrt(10))^2

c^2 = 2^2*(sqrt(10))^2

c^2 = 4*10

c^2 = 40

Using the pythagorean theorem, we see that

a^2 + b^2 = c^2

20 + 20 = 40

40 = 40

So the initial equation a^2 + b^2 = c^2 is true making the triangle with sides a,b,c defined above to be a right triangle

(2 * sq root 5)^2 = 20

20 + 20 = 40

2*sq root(10)^2 = 40

The sum of both sides squared = hypotenuse squared.

By the Pythagorean Theorem, we know that this is a right triangle.

Step-by-step explanation:

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".