One more! < 3 all of these questions were pretty different so i just need one final explanation!

To solve, use the following equation:

= (y₂ - y₁)/(x₂ - x₁)

Remember that each point contains one x, and one y: (x₁ , y₁) ; (x₂ , y₂)

4) What is the slope of the line that goes through (6 , 5) and (3 , 1)?

Let:

(x₁ , y₁) = (3 , 1)

(x₂ , y₂) = (6 , 5)

Put the corresponding numbers to the corresponding variable in the equation:

= (y₂ - y₁)/(x₂ - x₁) = (5 - 1)/(6 - 3) = 4/3

is your answer

5) The slope of the line that goes through (-3 , -5) and (-3 , -6) is ___.

Again, find the slope. Use the equation used above:

= (y₂ - y₁)/(x₂ - x₁)

Let:

(x₁ , y₁) = (-3 , -5)

(x₂ , y₂) = (-3 , -6)

Put the corresponding numbers to the corresponding variable in the equation:

= (y₂ - y₁)/(x₂ - x₁) = (-6 - (-5))/(-3 - (-3))

Remember that two negative = one positive

= (-6 - (-5)/(-3 - (-3) = (-6 + 5)/(-3 + 3)

Simplify.

= (-6 + 5)/(-3 + 3) = -1/0

Because the denominator is 0, the answer is , for there are infinite amount of solutions.

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