What is the range of the function f(x) = 4x + 9, given the domain d = {-4, -2, 0, 2}? a. r = {-7, -1, 9, 17} b. r = {-17, -9, -1, 17} c. r = {-7, 1, 9, 17} d. r = {1, 7, 9, 17}

Hello :

Answer :C

Because :

f ( - 4 ) = 4(-4)+9 = -16 +9 = -7

f ( - 2 ) = 4(-2)+9 = - 8 +9 = 1

f (0 ) = 4(0)+9 = 9

f ( 2 ) = 4(2)+9 = 17

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11