Solve the system by elimination state whether the system has one solution infinite solutions or no solution x+3y=-5 4x-y=6

one solution, i.e x = 1 and y = -2

Step-by-step explanation:

Given two equations :

x+3y = -5   (1)

4x - y =6   (2)

Using elimination method,

Multiply equation (2) by 3 and add it to equation (1)

We get,

x + 3y + {(4x - y)×3} = -5 +(6×3)

x + 12x + 3y - 3y = -5 + 18

13x = 13

x = 13/13  = 1

And corresponding y will be:

x + 3y = -5   , Plug x =1  to get y

1 + 3y = -5

3y = -5 - 1

y = -6/3 = -2

Hence we got only one solution, i.e x =1 and y = -2

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step-by-step explanation: