What is the quotient of y-5\sqrt{2y^2-7y-15} a. 2y + 3 b. 2y − 3 c. 2y − 17y r −70 d. 2y − 17y r 70

None of these

Step-by-step explanation:

y-5\√(2y2 - 7y -15)

On simplifying 2y2 - 7y -15, we get  

2y2 – (10-3)y -15

= 2y2 – 10y -3y-15

= 2y(y-5)-3(y-5)

= (2y-3)(y-5)

On squaring nominator and denominator we get  

(y-5)2/(2y-3)(y-5)

= (y-5)/(2y-3)

So the quotient becomes, 5/2  

While the remainder becomes 2.5

I think its A

Step-by-step explanation:

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step-by-step explanation:

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5