What are the x–coordinates of the three points where the graphs of the equations intersect? x3 – 10x = x2 – 6

(- 3, 0), (2 + , 0), (2 - , 0)

Step-by-step explanation:

rearrange the equation equating to zero

x³ - x² - 10x + 6 = 0

note that when x = - 3

(- 3)³ - (- 3)² - 10(- 3) + 6 = - 27 - 9 + 30 + 6 = 0, hence

x = - 3 is a root and (x + 3) is a factor of the polynomial

dividing x³ - x² - 10x + 6 ÷ (x + 3) gives

(x + 3)(x² - 4x + 2) = 0

solve x² - 4x + 2 = 0 using the quadratic formula

with a = 1, b= - 4 and c = 2

x = (4 ± )/ 2

  = (4 ± ) / 2

  = (4 ± 2) / 2

  = 2 ±, hence

x = 2 + , x = 2 -

intersect at (- 3, 0), (2 +, 0), (2 - , 0)

Step-by-step explanation:

First, move all terms to one side with zero on the other side so the Zero Product Property can be applied:

x³ - x² - 10x + 6 = 0    Possible rational roots are: ±{1, 2, 3, 6}

Use synthetic division to find one of the roots.  Let's try x = -3

-3 |  1    -1    -10    6

   |  ↓   -3    12    -6

      1    -4     2     0  ← remainder is zero, so x = -3 is a root/intercept

Next, evaluate the reduced polynomial x² - 4x + 2 = 0

This can not be factored so use the quadratic formula to find the remaining roots/intercepts:

a = 1, b = -4, c = 2

Intercepts are

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.

i would you but i don't under stand the qustion

step-by-step explanation: