Height of an object t seconds after it is launched is modeled by the function h(t) = -5t^2 + 30t + 200. the object will hit the ground in how many seconds.

10 seconds

Step-by-step explanation:

When the object hits the ground, the height (y-value) is 0.

h(t) = -5t² + 30t + 200

  0 = -5t² + 30t + 200   set height equal to zero

  0 = -5(t² - 6t - 40)      factored out -5

  0 = -5(t - 10)(t + 4)     factored the quadratic

0 = t - 10     0 = t + 4    applied the Zero Product Property

  t = 10         t = -4        solved for t

                        ↓

                    t = -4 is not valid (since time cannot be negative)

So, t = 10

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

what golf ball

step-by-step explanation: